def collatz number if number number return elif number number return p

  • Anonymous
  • Python
  • 21 May 2020 
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def collatz(number):

    if number % 2 == 0:

        x = (number // 2)

        return x

    elif number % 2 == 1:

        y = (3 * number + 1)

        return y





print('Wanna see some magic?\nType any positive integer number and I will transform it into 1!')

UserNumber = int(input())



result = collatz(UserNumber)

print(result)

while result != 1:

    NewResult = collatz(result)

    result = NewResult

    print(NewResult)

    if result == 1:

        print('It is Magic,\n bitch :)')
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