# sum sum I_1 sum sum sum I_3 sum const I_1 sub sub I_1 sub sub sub I_3

 ``` 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36``` ```//sum(x, 0) = ...(x) sum(x, 0) = I_1(x) //sum(x, y+1) = ...(x, y, sum(x, y)) sum(x, y+1) = s I_3(x, y, sum(x, y)) //p(0) = const p(0) = 0 //p(x+1) = ...(x, p(x)) p(x+1) = I_1(x, p(x)) //sub(x,0) = ...(x) sub(x,0) = I_1(x) //sub(x,y+1) = ...(x, y, sub(x, y)) sub(x,y+1) = p I_3(x, y, sub(x, y)) //sgn(0) = const sgn(0) = 0 //sgn(x+1) = ...(x, sgn(x)) sgn(x+1) = s o I_1(x, sgn(x)) //mul(x, 0) = ...(x) mul(x, 0) = o(x) //mul(x, y+1) = ...(x, y, mul(x, y)) = ...[...(x, y, mul(x, y)), ...(x, y, mul(x, y))] mul(x, y+1) = sum[I_1(x, y, mul(x, y)), I_3(x, y, mul(x, y))] //r(0) = const r(0) = 0 r(x+1) = s(r(x)) * sgn(5-s(r(x))) //для неё //r(x+1) = ...(x, r(x)) = ...[...(x, r(x)), ...(x, r(x))] r(x+1) = mul(s I_2(x, r(x)), f s I_2(x, r(x))) f(x) = sgn(sub(ssssso(x)), x) G(m, n) = r((m - 2) + (n - 3), 5) //для неё (условие) G(m, n) = r sum (A I_1(m ,n), B I_2(m ,n)) A(x) = sub(I_1(x), sso(x)) B(x) = sub(I_1(x), ssso(x)) ```