arr1 arr2 arr3 string_arr abracadabra somethingnewforus testandtestaga

  • Anonymous
  • Python
  • 17 Feb 2020 
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arr1 = [6, 5, 3, 5, 9, 5, 4, 4, 3, 2, 7, 3, 6, 7, 2]

arr2 = [7, 7, 4, 2, 8, 9, 2, 6, 4, 8, 8, 5, 7, 3, 2]

arr3 = [4, 6, 4, 4, 6, 5, 7, 9, 6, 6, 5, 7, 5, 5, 3]

string_arr = ["abracadabra", "somethingnewforus", "testandtestagain"]

dict1 = {2: 8, 5: 11, 7: 3, 1: 5, 45: 14}

dict2 = {3: 13, 5: 10, 8: 2, 1: 3, 45: 8, 4: 14}

words1 = ["q", "qq", "w", "w", "ww", "as"]

words2 = ["a", "q", "qq", "qq", "ww"]





# Exercise 1

def count_numbers(arr):

    counts = {}

    for i in arr:

        if i in counts:

            counts[i] += 1

        else:

            counts[i] = 1

    return counts





print('Exercise 1:')

print(count_numbers(arr1))

print(count_numbers(arr2))





# Exercise 2

def last_index(arr):

    indexes = {}

    for i in range(0, len(arr)):

        indexes[arr[i]] = i

    return indexes





print('Exercise 2:')

print(last_index(arr2))

print(last_index(arr3))





# Exercise 3

def all_indexes(arr):

    all_ind = {}

    for i in range(0, len(arr)):

        if arr[i] in all_ind:

            all_ind[arr[i]].append(i)

        else:

            all_ind[arr[i]] = [i]

    return all_ind





print('Exercise 3:')

print(all_indexes(arr3))





# Exercise 4

def count_letters(arr):

    arr_letters = []

    for word in arr:

        letters = {}

        for let in word:

            if let in letters:

                letters[let] += 1

            else:

                letters[let] = 1

        arr_letters.append(letters)

    return arr_letters





print('Exercise 4:')

print(count_letters(string_arr))





# Exercise 5

def add_dicts(d1, d2):

    for i in d2:

        if i in d1:

            d1[i] += d2[i]

        else:

            d1[i] = d2[i]

    return d1





print('Exercise 5:')

print(add_dicts(dict1, dict2))





# Exercise 6

def words_difference(w1, w2):

    diff = {}

    res = []

    for i in w1:

        if i in diff:

            diff[i] += 1

        else:

            diff[i] = 1

    for i in w2:

        if i in diff:

            diff[i] -= 1



    for i in diff:

        if diff[i] > 0:

            res.append(i)

    return res





print('Exercise 6:')

print (words_difference(words1, words2))
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