int input mino1 mino2 mino3 minc1 float inf minc2 float inf minc3 floa

  • Anonymous
  • Text only
  • 11 Feb 2020 
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n = int(input())

mino1 = 0; mino2 = 0; mino3 = 0

minc1 = [float('inf')]; minc2 = [float('inf')]; minc3 = [float('inf')]

minn = 0

res = 0

for i in range(n):

    a, b, c = map(int, input().split())

    if c <= b and c <= a:

        minn = min((a-c),(b-c))

        if minn % 4 == 1 and  minn // 4 <= minc1[-1]:

            minc1.append(minn // 4)

            mino1 += 1

        if minn % 4 == 2 and minn // 4 <= minc2[-1]:

            minc2.append(minn // 4)

            mino2 += 1

        if minn % 4 == 3 and  minn // 4 <= minc3[-1]:

            minc3.append(minn // 4)

            mino3 += 1

        res += (a + b)

    elif a <= b and a <= c:

        minn = min((b-a),(c-a))

        if minn % 4 == 1 and  minn // 4 <= minc1[-1]:

            minc1.append(minn // 4)

            mino1 += 1

        if minn % 4 == 2 and minn // 4 <= minc2[-1]:

            minc2.append(minn // 4)

            mino2 += 1

        if minn % 4 == 3 and  minn // 4 <= minc3[-1]:

            minc3.append(minn // 4)

            mino3 += 1

        res += (c + b)        

    elif b <= a  and b <= c:

        minn = min((a-b),(c-b))

        if minn % 4 == 1 and  minn // 4 <= minc1[-1]:

            minc1.append(minn // 4)

            mino1 += 1

        if minn % 4 == 2 and minn // 4 <= minc2[-1]:

            minc2.append(minn // 4)

            mino2 += 1

        if minn % 4 == 3 and  minn // 4 <= minc3[-1]:

            minc3.append(minn // 4)

            mino3 += 1

        res += (a + c)

minc1.remove(float('inf'));minc2.remove(float('inf'));minc3.remove(float('inf'))

if res % 4 == 0:

    print(res)

else:
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