Sorted dictionary

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# (IMHO) the simplest approach:
def sortedDictValues1(adict):
items = adict.items()
items.sort()
return [value for key, value in items]
# an alternative implementation, which
# happens to run a bit faster for large
# dictionaries on my machine:
def sortedDictValues2(adict):
keys = adict.keys()
keys.sort()
return [dict[key] for key in keys]
# a further slight speed-up on my box
# is to map a bound-method:
def sortedDictValues3(adict):
keys = adict.keys()
keys.sort()
return map(adict.get, keys)